\documentclass[12pt]{amsart} \usepackage{amsfonts} \usepackage{tikz-cd} \setlength{\topmargin}{0in} \setlength{\textheight}{10in} \setlength{\oddsidemargin}{0in} \setlength{\evensidemargin}{0in} \setlength{\textwidth}{6.5in} \parskip0.4em \thispagestyle{empty} \def\R{\mathbb{R}} \def\Z{\mathbb{Z}} \def\Q{\mathbb{Q}} \def\C{\mathbb{C}} \def\G{\mathbb{G}} \renewcommand{\phi}{\varphi} \begin{document} \begin{center} {\bf Math 113 Homework 11, due 4/16/2019} \end{center} \medskip \noindent {\bf 1.} Find all $x$ with $x^2 - 4 = 0$ in $\Z_5\times \Z_7.$ Now find all $x$ with $x^2-4 = 0$ in $\Z_{35}$ (by the Chinese remainder theorem, the two sets of solutions have the same cardinality and get sent to one another under the isomorphism that takes $a\in \Z_{35}$ to $(a\mod 5, a\mod 7)$). \bigskip \noindent {\bf 2.} Recall that the Gaussian integers $\G$ are complex numbers $a+bi$ with integer $a, b$. (a) Check that $\G\subseteq \C$ is a subring. (b) Let $n\in \N$ be a positive integer. For $z, z'\in \G$ we say that $z\equiv_n z'$ if $n\mid z'-z$. Recall (from problem set 4) that every class in $\G/\equiv_n$ can be uniquely represented by $a + bi$ for $a, b\in \{0,\dots, n-1\}$ remainders modulo $n$. You have checked in earlier homeworks that addition and multiplication are well defined on $\G/\equiv_n$, hence it is also a ring. Check that $\G/\equiv_3$ is a field (by finding an inverse for every element). This is a field with $9$ elements --- in fact, any other field with $9$ elements is isomorphic to this one! (c) Check that $\G/\equiv_5$ is not a field (hint: find a zero divisor). \bigskip \noindent {\bf 3.} 20.4, 20.5, \bigskip \noindent {\bf 4.} 20.8, 20.10 (the function $\phi(n)$ computes the number of residues mod $n$ which are relatively prime with $n$, so for example $\phi(p) = p-1$ for $p$ prime). \bigskip \noindent {\bf 5.} 20.23 (notation: ``unity'' means multiplicative identity element, ``unit'' means invertible element). \noindent {\bf 6.} Extra credit: 20.27, 20.28 \end{document}