Mathematicians

| Biography | His Work On Math (Newton's Contribution) | The Present | References | Back to the front page

The Present
Philip Chiu

In his mathematical papers, Newton applies his algorithm for the equation -rx+ tex2html_wrap210 +yy=0. He writes:

Example, [1st.] -rx+ tex2html_wrap210 +yy=0.

tex2html_wrap212 in y = -ry+ tex2html_wrap213 . tex2html_wrap214 . Therefore tex2html_wrap215

In modern day notation, Newton's formula involves partial derivatives with respect to x and y. He multiplies ''each terme of y tex2html_wrap174 eqat: by so many units as x hath dimensions in y tex2html_wrap180 terme'' and ''divides it by x & multiply by y for a numerator.'' In other words, he takes f tex2html_wrap218 multiplies by x and y and divides by x, ( tex2html_wrap219 , for a numerator. Then he multiplies ''each terme of y tex2html_wrap180 equation by soe many units as y hath dimensions in each terme & divide it by -y for a denom:'' In modern mathematical English, he means, take f tex2html_wrap221 multiply by y and its negative inverse, ( tex2html_wrap222 for a denominator. This of course results in the equation tex2html_wrap223 =-y* tex2html_wrap224 .