\(2^{15} = 32768\) and the sum of its digits is \(3 + 2 + 7 + 6 + 8 = 26\).
What is the sum of the digits of the number \(2^{1000}\)?
Once again, Python's code types save us from annoyingly complicated programming. The C-based solutions in the thread all seem to manually implement large integers, but Python has those built in, and I see no reason not to make full use of them!
def p16(b=2, p=1000):
n, res = b ** p, 0
while n > 0:
res += n % 10
n //= 10
return resOr, alternately, an approach that relies on string conversion but takes only a single line:
p16 = lambda b=2, p=1000: sum(map(int, str(b ** p)))