\def\bd{\bff d} \sect{Gouv\^ea-Mazur (type) Conjectures.} Let $N_{>0}\in \Z$, $p$ be a prime such that $(N,p)=1$ and $v=:v_p$ the valuation on $\C_p$ such that $v(\alp)=1$ and $|r|=p^{-v(r)}$. Let $\alp_{\ge0}\in\Q$. Then a normalized eigenform $F$, $$F(q)=\sum_{n\ge 0}a_nq^n$$ on $X_0(Np)$ over $\C_p$ is said to have slope $\alp$ if $v(a_p)=\alp$. For an integer $k$, let $\bff d (k,\alp)$ be the number of distinct such eigenforms of weight $k$. Suppose $p$ is odd for now.\sk \def\bd{\bff d} \proclaim Conjecture 1. If $k,k'>\alp+1$ and $k\con k' \mod p^\alp(p-1)$ then $$\bd( k,\alp)=\bd(k',\alp).$$\vfil Assume this for now and keep the notation.\sk \proclaim Conjecture 2. Suppose that $\bd(k,\alp)=1$. Let $F_k$ and $F_{k'}$ be the normalized forms predicted by Conjecture 1. Then $$F_k(q)\con F_{k'}(q)\mod p(k-k') $$\sk \proclaim Conjecture 3. Suppose $\bd(k,\alp)=d$ and for $j>\alp+1$, $j\con k\mod p^\alp(p-1)$ $F_{j,1},\dots, F_{j,d}$ are the $d$ forms of slope $\alp$ and weight $j$. $$\sum_{i=1}^dF_{j,i}(q)\con \sum_{i=1}^dF_{k,i}(q)\ \mod p(j-k).$$\sk \proclaim Conjecture 4. There is a geometric/ring theoretic explanation of all this. Hida theory establishes all 4 conjectures when $\alp =0$.\sk \sect{Conjecture 1 and the Eigencurve} $p$ may be 2 now. Let $\cW$ be the space of continuous characters $\Z_p^*\ra\C_p^*$. If $k\in\Z$ define $\chi_k\in \cW$ by $$\chi_k\colon a\to a^k.$$ If $\chi,\psi\in\cW$, set $$d_\cW(\chi,\psi)=\sup_{a\in\Z_p^*}|\chi(a)-\psi(a)|.$$\sk There is a rigid analytic curve $X=:X_N$ whose points correspond to overconvergent eigenforms of tame level $N$ and finite slope. In particular, for each $x\in X$ there is a $q$-expansion $$F_x(q)=\sum_{n\ge0}\cA_n(x)q^n.$$ In fact the $\cA_n$'s are rigid analytic functions on $X$. Set $\alp(x)=v(\cA_p(x))$. \sk If $x,y\in X(\C_p)$, set $$d_X(x,y)=\sup_{n\ge 0}|\cA_n(x)-\cA_n(y)|.$$ There is also a natural map $\kappa\colon X\ra \cW$. Moreover, $$d_{\cW}(\kappa(x),\kappa(y))\le d_{X}(x,y).$$\sk For $\bet_{\ge0}\in\Q$ and $\chi\in \cW$, let $$B_{\bet}(\chi)=\stt{\psi\in\cW\colon d(\psi,\chi)< |p|^{\bet}},$$ $$X_{\alp}(\chi)=\stt{x\in X\colon \kappa(x)\in B_\alp(\chi), \alp(x)=\alp}.$$ Then $X_{\alp}(\chi)$ is a rigid subspace of $X$ and Conjecture 1 follows from \proclaim Conjecture 5. $X_{\alp}(\chi)$ is finite and flat over $B_\alp(\chi)$.\sk \beginsection Lipshitz functions Suppose $(Y,d)$ is a rigid space over $K$ with a metric on $Y(\C_p)$. A {\bf Lipshitz function} on $Y$ with respect to $d$, is a rigid analytic function $f$ such that for $x,y\in Y(\C_p)$ $$|f(x)|\le 1\ \hba\ |f(x)-f(y)|\le d(x,y).$$ Let $\Lambda_K(Y,d)$ (or $\Lambda(Y)$) denote the ring of Lipshitz functions on $Y$ over $K$ wrt $d$.\sk \exs (i) $\Lambda(\cW)=\Z_p[[\Z_p^*]]$\vskip.5cm \ni Suppose $r,R\in \Z_p$ $0<|r|\le|R|\le 1$. Then $$\Lambda (A(|r|,|R|))=\Z_p\oplus r\Z_p{[[r/T]]}\oplus R\Z_p[[T/R]].$$ All previous conjectures follow from Conjecture 5 and, \proclaim Suspicion 6. If $Y\subset X$ is an affinoid finite and flat over its image $Z$ in $\cW$, is $\Lambda(Y)$ integral over $\Lambda(Z)$.\sk When there is only one normalized eigenform on $X_1(N\bq)$ ($\bq=4$ for $p=2$ and $p$ otherwise) of weight $k$, character $\eps$ for the action of $(\Z_p/\bq\Z_p)^*$ and slope $\alp$, then Suspicion 6 implies $\kappa\colon (X_\alp(\eps\chi_k),d_X)\ra (B_\alp(\eps\chi_k),d_\cW)$ is an isometry.\sk \beginsection Evidence When $\alp=0$ these conjectures and suspicions follow from Hida theory. Suppose $p=2$ and $N=1$. In this case Conjecture $5$ was proven by Emerton when $d_\cW(\chi,\chi_{14})\le 1/8$ and $\alp=\min\stt{6,-\log_2 d(\chi,\chi_{14})}$.\sk Moreover, Emerton also proves if $$Y_i=\stt{x\in X: \cases{ 2^{-\alp(x)}=d(\kappa(x),\chi_{14})>1/64,& $i=1$\cr \alp(x)=6, d(\kappa(x),\chi_{14})\le 14& $i=2$}},$$ the map from $Y_i$ to its image in $\cW$ is finite and flat of degree $i$ and one verify Suspicion 6 affirmatively for affinoids contained in $Y_i$ (all the ones I've tried so far anyway).\sk On $X_0(3)$ for $k_n=10+18n$, $0\le n\le 10$, Stein has shown there are exactly two normalized eigenforms of weight $k_n$ of slope $4$ for $p=3$ and if $A_{k_n}$ denotes the sum of their $U_3$ eigenvalues, $$v_3(A_{10}-A_k) = 1+v_3(k_n-10).$$\sk But, Suspicion 6 can't be true in general. On $X_0(6)$, for $k_n=8+8n$, $0\le n\le 8$, Stein has shown that there are three forms of weight $k_n$ of slope $3$ for $p=2$ and if $A_k$ denotes the sum of their $U_2$ eigenvalues $$v_2(A_8-A_{k_n})=1+v_2(k_n-8).$$\vfil This is a problem? \sk \end \sect{ Infinite Slope} There are eigenforms with $a_p=0$. We know that if $F$ is a classical eigenform of weight $k$, tame level $N$ and finite slope, there exists a sequence of classical eigenforms $F_n$ of tame level $N$ and weight $k_n$ such that $k_n\ra\infty$ and \pad ally $$F_n(q)\ra F(q).$$ \proclaim Question. What happens if $F$ has infinite slope?\sk Suppose $\omega\in \cW$ is the Teichm\"uller character. Let $F^{\omega}$ the form with \qe $$\sums{n\ge 1}_{p\not|n}a_n\omega(n)q^n.$$ Then $F^{\omega}$ is a classical eigenform of infinite slope. In response to a question of Jochnowitz, we've proven, \proclaim Theorem. If $F$ has finite slope there exists classical eigenforms $F_n$ of finite slope on $X_1(N)$ such that \pad ally, $$F_n(q)\ra F^\omega(q).$$ But how big must the weights be to get a given closeness?\sk Let $$\Delta(q)=q\prod(1-q^n)^{24}.$$ Stein found newforms of weights $12+2\cdot 3^{n-1}$ and on $\Gamma_0(3)$ congruent to $\Delta^{\omega_3}(q)$ modulo $3^n$ for $n=1, 2,3,4$. What about non-twist infinite slope forms?\sk The form $$ f = q + 6q^2 + 4q^4 - 6q^5 - 40q^7+\cdots$$ is a non-CM, non-twist eigenform in $S_6(\Gamma_0(9))$. Stein found for $n=1,2,3,4$ there is a newform in $S_{6+2\cdot3^{n-1}}(\Gamma_0(3))$ that is congruent to $f$ modulo $3^n$.\sk On the other hand\dots Let $$ f = q - 2q^4 - q^7 + 5q^{13} + \cdots$$ be the weight $2$ normalized form on $X_0(27)$. Then if $g$ is a normalized eigenform of weight $2+2\cdot3^{n-1}$, $n\le 4$, on $\Gamma_0(3)$ $v_3(g(q)-f(q)) \le 1$.\sk \beginsection Fixed weight Suppose you fix the weight and let the slope tend to $\infty$. This only makes sense when one talks about \pad\ modular forms. Lawren Smithline observed: ``Let $R_n$ be the number of congruence classes mod $3^n$ after 3-deprivation [of overconvergent $3$-adic weight 0 eigenforms of tame level 1.] (One can also avoid the 3-deprivation issue by throwing out a few forms of lowest slope.)" From, computations involving the first $33$ such forms he observed, ``The sequence ${R_1, R_2, ...}$ [seems to] begin $1, 2, 2, 4, 8.$" and conjectured, $$R_n = R_{n-2} + 2.3^{n-4}.$$ What this suggests is that there are an uncountable number of overconvergent modular eigenforms of weight 0 of tame level 1. \beginsection Other Questions\dots